Question 1.1. What is the solution of log4(2x 6) = 2?
(Points : 1)
5

7

11

14

Question

Question 1.1. What is the solution of log4(2x  6) = 2?
(Points : 1)
       5

       7

       11

       14

ranga · Answer

Something is missing between 2x and 6 within the parenthesis.

anonymous · Answer

It is subtraction between the 2x and 6...

anonymous · Answer

Non of your option are correct

ranga · Answer

$$If ~~\log_B(A) = C, ~then~~A = B^C\If ~~\log_4(2x-6) = 2, ~then~~2x-6 = 4^2 = 16.  ~~\text{  Solve for x.}$$

anonymous · Answer

Ohhhh, so it's 11! Thank you so so much!!

anonymous · Answer

I have another one I am confused about as well.. @ranga

anonymous · Answer

attachment

ranga · Answer

$$log_B(A) - log_B(C) = log\left(\frac AC\right)\log_{36}(x+4)-log_{36}(2x-14) = log_{36}\left(\frac{x+4}{2x-14}\right) = \frac 12\\left(\frac{x+4}{2x-14}\right) = 36^{\frac 12} = \sqrt{36} =6.\quad \text{Solve for x.}$$