Question

Center at (0,0) r=8

Answer 1

Hey? Why did you leave, don't be so not patient please! You are probably looking for the equation of the circle in a \(\large\color{blue}{ \bf (x-h)^{2}+(y-k)^{2}=r^{2} }\) form.

your center is (h,k) in this case, (0,0)
so h=0, and k=0. You also know that radius is equal to 8.

PLUG EVERYTHING IN......

\(\large\color{blue}{ \bf (x-h)^{2}+(y-k)^{2}=r^{2} }\)
\(\large\color{blue}{ \bf (x-0)^{2}+(y-0)^{2}=8^{2} }\)
\(\large\color{blue}{ \bf (x)^{2}+(y)^{2}=8^{2} }\) See how I am doing this ?

\(\large\color{blue}{ \bf x^{2}+y^{2}=64 }\) there is the equation you need :)

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Answer 2

Thank you so much be one of my fans and i will do the same

Answer 3

Don't ask people to fan you on this website, it is not very much according to the policy.. but if you want, I can certainly fan you. You don't need to fan me back for that...

have a good day!

Answer 4

okay thank you I'm new to this

Answer 5

YES... I can see this based on your smart score (of 19), but it doesn't matter. Everyone was new to this at some point.