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Mathematics 10 Online
OpenStudy (anonymous):

Question on this?

OpenStudy (anonymous):

Center at (0,0) r=8

OpenStudy (anonymous):

I thought it was B but i got it wrong.

OpenStudy (anonymous):

@vzfreakz do you have any idea on this?

OpenStudy (anonymous):

Th

OpenStudy (anonymous):

@HelloKitty/Trun what is that?

OpenStudy (johnweldon1993):

We can use the fact that We know 2 sides and an angle (instead of calculating the height of this triangle) We want the area with angle A known so \[\large Area = \frac{1}{2}bc \sin(A)\] So we take the fact that A = 25 And both B and C are 20...and we make that equation \[\large Area = \frac{1}{2}(20)(20) \sin(25)\] \[\large Area = 200\sin(25)\] \[\large Area = ?\]

OpenStudy (johnweldon1993):

Do you want to do it like that? Or would you like to have calculated the height and gone from there?

OpenStudy (anonymous):

I'm extremely Lost to be honest with you does the other way make more since?

OpenStudy (johnweldon1993):

Possibly :) lol Alright...so we have |dw:1398982333832:dw| Right?

OpenStudy (johnweldon1993):

|dw:1398982372742:dw|

OpenStudy (anonymous):

yeah the second picture

OpenStudy (johnweldon1993):

We know the area of a triangle is \[\large \text{Area} = \frac{1}{2} \text{Base} \times \text{Height}\]

OpenStudy (johnweldon1993):

So we need to figure out the height...since we know that the base will be 20

OpenStudy (johnweldon1993):

Well, the height would be |dw:1398982469753:dw|

OpenStudy (johnweldon1993):

Everything good so far?

OpenStudy (anonymous):

yeah everything look just about right

OpenStudy (johnweldon1993):

Great... Now...to find that height, we need to notice that |dw:1398982580162:dw| We have a right triangle

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