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Mathematics 9 Online
OpenStudy (anonymous):

anybody know how to verify the identity? I've never done this before and my text don't cover this. i never learned this in actual school either so i need help from somebody who does.

OpenStudy (anonymous):

OpenStudy (anonymous):

What do you mean by verifying an identity? You mean you need a proof? Or a derivation?

OpenStudy (anonymous):

I might start with cot x = cos x / sin x and tan x = sin x /cos x and then see how these behave for angle offset by pi/2.

OpenStudy (helder_edwin):

i would do it as advised: \[\large \cot(x-\pi/2)=\frac{\cos(x-\pi/2)}{\sin(x-\pi/2)}= \] \[\large =\frac{\cos x\cos(\pi/2)+\sin x\sin(\pi/2)} {\sin x\cos(\pi/2)-\sin(\pi/2)\cos x}= \frac{\sin x}{-\cos x}=-\tan x \]

OpenStudy (anonymous):

@helder_edwin Can you please explain how did you get cos(x - pi/2) = cosxcos(pi/2) +sinx(sinpi/2)? Which property did you use?

OpenStudy (helder_edwin):

it is a tryg identity: \[\large \cos(x-y)=\cos x\cos y+\sin x\sin y \]

OpenStudy (anonymous):

and what property did you use to get to the step before the last?

OpenStudy (anonymous):

@helder_edwin

OpenStudy (helder_edwin):

\[\large \cos(\pi/2)=0 \] \[\large \sin(\pi/2)=1 \]

OpenStudy (helder_edwin):

it is the demonstration of the identity u posted.

OpenStudy (anonymous):

Okay thank you i just wanna make sure. (:

OpenStudy (anonymous):

what?how? i cant lol

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

You're welcome.

OpenStudy (anonymous):

I still need help if anybody is willing to help meeee

OpenStudy (anonymous):

Hi!

OpenStudy (anonymous):

Hey! lol

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

:D

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