Question

i dont get this very well

Answer 1

Tan(2) is just a number. If the program doesn't want an EXACT answer, you can actually use a calculator to see what that number is and plug it in. If they do want an exact answer, just treat the entire thing as a single number.

Either way, solve for x as normal. Multiply both sides by x, first.

Answer 2

Oh, it says "to the nearest tenth," so an exact answer isn't necessary. You can plug in a number for Tan(2), just remember to use at least the hundreths place.

Answer 3

hmm still a bit confused :/

Answer 4

Use a calculator. Put in Tan(2) and press enter. It gives you a number.

Tan(2) is just a number. We can call it a.

\[a = \frac{4}{x}\]

Solve for x.

Answer 5

this is the number i got -2.18503986326

Answer 6

Your calculator is on radians (you want it in degrees), but you can see that it's just a number :)

Answer 7

So, if someone gave you the equation:
\[a=\frac{4}{x}\]
What does x equal?

Answer 8

i'm not sure :/

Answer 9

\[a = \frac{4}{x}\]
Multiply both sides by x:
\[x*a = x * \frac{4}{x} = 4\]
Divide both sides by a:
\[\frac{ax}{a} = \frac{4}{a}\]
\[x = \frac{4}{a}\]

Right?

Answer 10

yes

Answer 11

Alright. and a = Tan(2)

So, we have our answer:
\[x = \frac{4}{Tan(2^o)}\]
Throw that into a calculator, and you're done! (Make sure your calculator is in degrees. The answer should NOT be negative.)

Answer 12

-1.83063

Answer 13

i don't know how to put it in degree mode

Answer 14

Tan(2) = .0349207695

Answer 15

how would i round that?

Answer 16

To the hundredths place, at the most. You can just use it and round the result, as well.

Answer 17

i need to round it to the nearest tenth

Answer 18

Right, which you'll do before you put in the answer.

Answer 19

how would i round it ?

Answer 20

First, divide 4 by Tan(2). What do you get?

Answer 21

idk nvm

Answer 22

\[\frac{4}{Tan(2^o)} = \frac{4}{.0349207695} = 114.5450131\]

Round to the tenths place.

Answer 23

114.5

Answer 24

There ya go :)

Answer 25

haha thank you!

Answer 26

My pleasure :)