Help please! solve the definite integral integral of e^(2x)/(1+e^(2x)) dx from 2 to 4
Do a u-sub.
so the u value would be 1+e^(2x)?
Yes, now find what du would be.
so du=2(e^(2x)) dx
which then becomes 1/2du=e^(2x)dx
Right! So now all you have to integrate is \[\LARGE \frac{1}{2} \int \frac{1}{u}~du\]
Forgot the limits \[\LARGE \frac{1}{2} \int_{2}^{4} \frac{1}{u}~du\]
so that would be... \[1/2 \int\limits_{2}^{4}\ln u\]
oops sorry i mean \[(1/2)\ln(u)\]
Yup, now plug in what u is and evaluate it.. \[\LARGE \frac{ln|1+e^{2x}|}{2}|_{2}^{4}\]
so the answer would be...about 2
1.9910927 to be exact, but approx 2 yes :)
awesome :D would leaving it just at 2 be ok?
Depends on what your instructions or instructor wants.. USUALLY they like rounded decimal answers. But just 2 should be fine.
ok awesome :) thank you so much!
You're welcome, and good luck! :P
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