Question

Definite integral:

Answer 1

http://prntscr.com/3fdzdt

Answer 2

just separate out the denominator..

Answer 3

(a+b)/c = a/c+b/c

Answer 4

I tried this.. does it look right?
\[\Large \int_{1}^{61} \frac{1+x^{1/3}}{\sqrt{x}}=\int_{1}^{61} \frac{1}{\sqrt{x}}+\int_{1}^{61} \frac{x^{1/3}}{x^{1/2}}\]
Which gave me
\[\Large \int_{1}^{61}\frac{1}{\sqrt{x}}+\int_{1}^{61}\frac{1}{x^{1/6}}\]
Integrating it..
( \((\Large 2\sqrt{x}+\frac{6}{5}x^{5/6})|_{1}^{61})\) )
Am I right so far?

Answer 5

I was trying that :P

Answer 6

i thought upper limit is 64

Answer 7

everything else is correct :)

Answer 8

Whoops, sorry I'm too tired for this >.<

But thanks hartnn :D

Answer 9

welcome lui ^_^

Answer 10

see if you get final answer as 256/5 :)

Answer 11

Yup.. once I changed the 61 to a 64 that was xD

Answer 12

Oops