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OpenStudy (anonymous):
how can i write the following equation in the below form
12 years ago
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OpenStudy (anonymous):
\[(1-x)^{\frac{1}{2}} (1+x)^{\frac{3}{2}}\]
to
(1 + x)√(1 − x^2).
@Vincent-Lyon.Fr
12 years ago
OpenStudy (amistre64):
anything that is /2 is a sqrt to begin with. then it may just be a matter of reducing whats left; unless you want to reduce the exponents to begin with
12 years ago
OpenStudy (amistre64):
\[a^{1/2}b^{3/2}\]
\[a^{1/2}~b^{2/2+1/2}\]
\[a^{1/2}~b^{2/2}~b^{1/2}\]
\[b(a^{1/2}b^{1/2})\]
etc...
12 years ago
OpenStudy (anonymous):
\[(1-x)^{\frac{1}{2}}(\sqrt{1-x})^3\]
12 years ago
OpenStudy (anonymous):
ohhh
12 years ago
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OpenStudy (amistre64):
and ideally, your notation would be corrected as:\[(1-x)^{\frac{1}{2}}\sqrt{~(1-x)^3~}\]
12 years ago
OpenStudy (amistre64):
lol, and with a + in it ... but its early
12 years ago
OpenStudy (anonymous):
\[(1+x)(\sqrt{1-x}\sqrt{1+x})\]
12 years ago
OpenStudy (amistre64):
yep, and how do conjugates multiply?
12 years ago
OpenStudy (anonymous):
hmmm?
12 years ago
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OpenStudy (amistre64):
(m-n)(m+n)
conjugates are binomials with opposite operation ...
(m-n)(m+n) = m^2 - n^2
12 years ago
OpenStudy (anonymous):
yeah then it should be
\[(1+x)(\sqrt{1-x^2})\]
12 years ago
OpenStudy (anonymous):
is tht right?
12 years ago
OpenStudy (anonymous):
lol just realised that i got the answer :)
12 years ago
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