The differential equation dy/dx = (x+1)/(x-2)
The differential equation \[\frac{ dy }{ dx } = \frac{ x+1 }{ x-2 }\] I. produces a slope field with horizontal tangents at x = -1 II. produces a slope field with vertical tangents at x = 2 III. produces a slope field with rows of parallel segments I only II only I and II only all of them II and III only
I. No. It's at x = +1 II. Yes. x = 2 makes the denominator explode. III. You tell me.
i would assume that III is correct, because is vertical tangents, wouldnt it be parallel?
?? Not sure that makes any sense.
actually mb, its not parallel because tangents arent straight lines are they?
?? You seem to be struggling with exactly what a Slope Field is. As we get away from x = 0, far away, the slope tends toward +1 At x = -1, we have 0/(-3) = 0. So actually, I is good. It is tangents are horizontal for x= -1. You should have argued with me on that point.
Join our real-time social learning platform and learn together with your friends!