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Find the domain for the particular solution to the differential dy/dx = 3y/x, with initial condition x>0 x<0 |x|<=0 x is not equal to 0 all real numbers
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the equation is \[\frac{ dy }{ dx }=\frac{ 3y }{ x }\]
\(\frac{dy}{dx}=\frac{3y}{x}\implies\int\frac{1}{3y}dy=\int\frac{1}{x}dx\implies\frac{\ln(y)}{3}=\ln(x)+c\\\implies ln(y)=3\ln(x)+c_0\implies y = e^{3ln(x)+c_0}\implies y = e^{3\ln(x)}e^{c_0}\\\implies y = c_1e^{\ln(x^3)}\implies y=c_1x^3\)
domain range is all real numbers for \(c_1\ne 0\)
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