Multivariable Calculus, https://www.dropbox.com/s/x0vwzhtcbj5j2fl/2014-05-03%2011.11.06.jpg Exercise 61, Please help me do it?
treat \(y\) as constant when u work \(\dfrac{\partial z}{\partial x}\)
thats what i see https://www.dropbox.com/s/uq2e8gjouxmygf6/Screenshot%202014-05-03%2011.53.34.jpg
i think latex is not working..
could you please help me solve this one only just so that I get the idea please???
(x^2+y^2+z^2)^(3/2) = 1 simplify the equation a bit : x^2+y^2+z^2 = 1
next, differentiate both sides with.respect.to "x"
just treat "y" as constant
as @ganeshie8 says, the answer would be \[2x + 2z \frac{\partial z}{\partial x} = 0 \Rightarrow \frac{\partial z}{\partial x} = - x / z\] if $$z \neq 0$$ undefined otherwise
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