Question

Solve for x. Round to nearest tenth.

Answer 1

I have to solve for both of them using the same "Solve for x. Round to nearest tenth."

Answer 2

use sin35=x/20
and cos62=50/x

Answer 3

How does that work?

Answer 4

I need a little more information I do not completely understand the concept of sin or cos or how working them out would work

Answer 5

sina=perpendicular distence/length of hypotenuse
cosa=lenght of base/length of hypotenuse

Answer 6

That will give me the answer to the two questions? sina for the first and cosa for the second?

Answer 7

sin35 = -0.428?

Answer 8

cos62 = 0.673?

Answer 9

sin35=0.5735 and cos62=0.469

Answer 10

How did you get those because I entered them into the calculator and got different answer

Answer 11

I put cos62 then pushed = and it came up with .673

Answer 12

check the mode it's in radian calculate them in degree

Answer 13

switched it over and got the correct answer okay so where do I go now that I got the .573 and the .469?

Answer 14

yes now plug them on above equations and solve for x

Answer 15

plug them into what equation?

Answer 16

these equations
sin35=x/20
and cos62=50/x

know how to get them ?

Answer 17

Yes I just got them on the calculator
Sin35 = .573
Cos62 = .469
but now what do I do with those numbers?

Answer 18

sin 35 = x/20

0.573 = x/20

x= 0.573 * 20 = ...
like this

Answer 19

but the important point is whether you can get those equations on your own

Answer 20

oh okay thank you! and that is the answer for X perfect!

Answer 21

I did get them on my own, I got them wrong at first because the calculator was on RAD and not DEG but I changed it over and got the correct numbers

Answer 22

i wasn't talking about the values, i was talking about the equation

sin 35 = x/20
you could get this on your own ?

Answer 23

yeah ... .573 * 20 = 11.46

Answer 24

\(\huge \cos \theta =\dfrac{adjacent ~side }{hypotenuse} = \dfrac{a}{c} \)
\(\huge \sin \theta =\dfrac{opposite ~side }{hypotenuse} = \dfrac{b}{c} \)