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OpenStudy (anonymous):
Use Property 1 for radicals to simplify the following radical expression as much as possible. Assume the variable represents a positive number.
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OpenStudy (anonymous):
\[2a \sqrt[3]{8a^4}\]
hartnn (hartnn):
factor 8
OpenStudy (anonymous):
4,2
hartnn (hartnn):
factor it further
OpenStudy (anonymous):
2,2
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hartnn (hartnn):
so
8 = 2*2*2 = 2^3
right ?
\(x^4 = x \times x \times x \times x = x^3 \times x\)
got this ?
OpenStudy (anonymous):
I think so...
OpenStudy (anonymous):
Oh, yea i got it
hartnn (hartnn):
i am paring 3 constants and variables this time (instead of 2 which i did last time) because in this case, its cube root, instead of square root
OpenStudy (anonymous):
ok, I'm ready
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hartnn (hartnn):
\(\large \sqrt[3]{\heartsuit ^3}= \heartsuit\)
hartnn (hartnn):
\(\large \sqrt[3]{\heartsuit ^3}= (\heartsuit)^{3/3}= \heartsuit \)
OpenStudy (anonymous):
2
hartnn (hartnn):
\(\Large 2a \sqrt[3]{8a^4} = 2a \sqrt[3]{8} \sqrt[3]{a}\sqrt [3]{a^3}=..\)
hartnn (hartnn):
\(\Large 2a \sqrt[3]{8a^4} = 2a \sqrt[3]{2^3} \sqrt[3]{a}\sqrt [3]{a^3}=..\)
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OpenStudy (anonymous):
I know the 3s cancel out
hartnn (hartnn):
so
\(\Large 2a \sqrt[3]{8a^4} = 2a \times 2 \times \sqrt[3]{a}\times a=..\)
got this ?
OpenStudy (anonymous):
yup
hartnn (hartnn):
simplify
OpenStudy (anonymous):
4a?
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hartnn (hartnn):
2a times 2a = 4a^2
\(\Large 4a^2 \times \sqrt[3]a\)
thats it!
OpenStudy (anonymous):
Ohhhhhh! Thanks
hartnn (hartnn):
welcome ^_^
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