Question

2sin2x-cosx=0

Answer 1

Do you want the answer or how to do it?

Answer 2

how to solve it and how to do it

Answer 3

In the end you want the equation to be A - A= 0 where A is any number. So what value of x will give you the same answer for both the 2sin2x and cos x?

Answer 4

\(\bf {\color{brown}{ sin(2\theta)}}=2sin(\theta)cos(\theta)
\\ \quad \\ \quad \\

2sin(2x)-cos(x)=0\implies 2\cdot {\color{brown}{ 2sin(x)cos(x)}}=cos(x)
\\ \quad \\
4sin(x)=\cancel{ \cfrac{cos(x)}{cos(x)} }\)

solve for sin(x), then take arcsine to both sides to get "x"

Answer 5

3 sin^2x-7 sinx+2=0 ?

Answer 6

?

Answer 7

3 sin(squared)x- 7sin x=2=0

Answer 8

well, "x" is not that

Answer 9

cos x sin x- sinx=0
solve the equation in the interval [0,2pi)