Question

Calculus 2 SOS
Find the formula of the nth term of the following sequences:
1/1, -1/4, 1/9
and: 3/6, 4/7, 5/8

Answer 1

The first sequence has two components to it. First, the numerator switches between negative one and positive one. So, we would express that as (-1)^(n+1). The second component is the denominator, which can be expressed as n^2. So, in total, we have ((-1^(n+1))/(n^2).

The second sequence involves simple addition. The numerator starts at 3 and increases by one each time (n+2). The denominator does the same thing, but starts at 6 (n+5). In total, it would be expressed as (n+2)/(n+5).

Answer 2

\[\frac{n}{n^2}\]

Answer 3

and the second one, is

\[\frac{n+1}{(n+1)~~+1}\]

you see what I am trying to say right ?

Answer 4

By the way, this is trig, not calculus 2

Answer 5

its of AP I think