2700=300*2^(10x) , solve for x.

Question

anonymous · Answer

similar to your prev question but use log instead of ln :)

anonymous · Answer

not exactly
you need the change of base formula for this one

anonymous · Answer

how?

campbell_st · Answer

this is another log question

divide both sides by 300 and you get

$$9 = 2^{10x}$$

so the question is basically asking 2 to what power is 9

so you will need to take the log of both sides... base e or base 10... doesn't matter

$$\log(9) = \log(2^{10x})$$

there is a log law that applies to powers

$$\log(a^b) = b \times \log(a)$$

apply the law and then you'll be able to solve for x

anonymous · Answer

divide both sides by 300 first b/f using log.

anonymous · Answer

$$b^x=A\iff x=\frac{\ln(A)}{\ln(b)}$$
you have 
$$9=2^{10x}\iff 10x=\frac{\ln(9)}{\ln(2)}$$

anonymous · Answer

x=log(9)
__________
   10*log(2) 


correct?

anonymous · Answer

i thought LN was used only with e ?

anonymous · Answer

yes that is correct, what you have
change of base and of course a calculator if you want the numeric answer

anonymous · Answer

I also get x=ln(9)
               ________
               10*ln(2)

campbell_st · Answer

the answer will be the same... if you use base 10 or base e logs..... 

it will also be the same as long as the use the same base log in the numerator and denominator