z=2/3(x^3/2+y^3/2), 0 less than or equal to x less than or equal to 5, 0 less than or equal to y less than or equal to 3, I worked it out as a double integral and got 65.5 but does not match any of the answer choices on my sheet was wondering if someone one could work it out and see what they get. Thanks

Question

ganeshie8 · Answer

im getting 190

anonymous · Answer

answer choices are as follow

anonymous · Answer

36.238
38.031
31.017
29.973
33.018

anonymous · Answer

not sure what i am doing wrong no instruction or directions are given in the problem just that

anonymous · Answer

not sure what else to do just though it would be a double integral and that is all

anonymous · Answer

hello?

ganeshie8 · Answer

may i knw why are u evaluating doule integral... and whats the complete quesiton ?

anonymous · Answer

friend told me to do it that way and I tried it now that I got home

anonymous · Answer

that is the entire question

ganeshie8 · Answer

could u possibly take a snapshot and attach ?

anonymous · Answer

yes

anonymous · Answer

ill have it in a bit hopefully if i learn the hang of this chromebook lol

anonymous · Answer

attachment

anonymous · Answer

is that ok enough for you

anonymous · Answer

ITs a bonus question and when I printed it the top with the instructions was cut off

anonymous · Answer

ill ask him real quick what it says

ganeshie8 · Answer

oh ok, im also getting the same answer as u : http://www.wolframalpha.com/input/?i=%5Cint_0%5E5+%5Cint_0%5E3++2%2F3%28x%5E%283%2F2%29%2By%5E%283%2F2%29%29+dy+dx

anonymous · Answer

professor said he would make the five bonus problems calculus 3 problem even though we are in calculus 2 I thought you learned double integrals thast why my friend told me that yea I should try it that way but let me ask this other guy if the instructions printed out

anonymous · Answer

okay he said that it says something about area of surface

anonymous · Answer

hope you undertood that english is not my first language so sorry

anonymous · Answer

not sure what it means by area of surface havent learned that yet hope to learn it next year though but if you know how to do it I would like to get a preview right now if thats ok with you

anonymous · Answer

attachment

anonymous · Answer

he sent me this hope that clarifys it a bit its not of high quality but it is sort of readable

ganeshie8 · Answer

yes it clarifies everything :)

anonymous · Answer

this is next level stuff so I do not ndertsand  it but if you could kinda of explain it to me to prepare for next year( thats what he wants us to do the professor) i would be happy about thhat

ganeshie8 · Answer

sure :)
first let me just say what u were trying earlier :   65.5 is the VOLUME under the given function. Its not the surface area.

anonymous · Answer

oh ok

anonymous · Answer

would you do something like triple integrating to fine the surface area or what would you do

ganeshie8 · Answer

nope, double integral will do

anonymous · Answer

oh ok

anonymous · Answer

is there an extra step I have to take?

ganeshie8 · Answer

do u knw how to find "arc length" in calcII ?

anonymous · Answer

I honestly do not remember covering that but let me take a look at my notes

anonymous · Answer

theres nothing here on arc length sorry

ganeshie8 · Answer

no need, its not necessary

anonymous · Answer

we have done integration l hopitals series and other stuff like that

ganeshie8 · Answer

http://tutorial.math.lamar.edu/Classes/CalcIII/SurfaceArea.aspx

anonymous · Answer

also some basic diff equations

anonymous · Answer

but no arc lenght

anonymous · Answer

oh so its not needed then

anonymous · Answer

so how would we do it? sorry

anonymous · Answer

am i still talking with someone I have no clue how this website works its my first time sorry

ganeshie8 · Answer

look up the link i gave u earlier

anonymous · Answer

the video link

anonymous · Answer

that one?

ganeshie8 · Answer

http://tutorial.math.lamar.edu/Classes/CalcIII/SurfaceArea.aspx

ganeshie8 · Answer

if you want the answer : 33.018 http://www.wolframalpha.com/input/?i=%5Cint_0%5E3+%5Cint_0%5E5+sqrt%28x%2By+%2B+1%29+dx+dy

anonymous · Answer

Thanks

anonymous · Answer

For answer and vidoe link

anonymous · Answer

one more question though for a volume problem like this, find the volume under z=x^5+y^5 and above the region bounded by y=x^2 and x=y^2 would you do just a double integral then

anonymous · Answer

you said that when i did the double integral for the last problem and got 65 i believe it was to get the voluem

anonymous · Answer

would I do the same here for that problem

anonymous · Answer

and how would I set it up if it were a double integral problem I am jsut beginning with these double integrala nd would not knwo how to set this one up

ganeshie8 · Answer

yes but u need to setup the bounds correctly

anonymous · Answer

oh ok

anonymous · Answer

but how would you set it up im sorry

anonymous · Answer

wow I am already seeing how hard cal 3 is going to be its start to scare me hehe

ganeshie8 · Answer

its not hard if u start from beginning

anonymous · Answer

became a fan of you hehe you are very helpful

anonymous · Answer

really its not hard

ganeshie8 · Answer

http://ocw.mit.edu/courses/mathematics/18-02-multivariable-calculus-fall-2007/video-lectures/lecture-16-double-integrals/

ganeshie8 · Answer

i like that video ^
it teaches EVERYTHING about double integrals in a simple manner in just 30 minutes

ganeshie8 · Answer

watch it and let me knw if u have any questions

anonymous · Answer

i will thanks

anonymous · Answer

but can you jsut fnish off these problem with me I have to go to bed after this and work tomorrow hehe

ganeshie8 · Answer

we're already done wid the current problem right ?

ganeshie8 · Answer

http://www.wolframalpha.com/input/?i=%5Cint_0%5E3+%5Cint_0%5E5+sqrt%28x%2By+%2B+1%29+dx+dy

anonymous · Answer

i meant fir the new problem though

ganeshie8 · Answer

whats the new problem ?

anonymous · Answer

it was find the volume under z= x^5+y^5 and above the region bounded by y=x^2 and x=y^2

anonymous · Answer

did I send it , i might have not

anonymous · Answer

maybe i just thought i did ...sorry if i did

anonymous · Answer

I was talking about this one for the last couple of minutes

ganeshie8 · Answer

the double integral for volume wud be : http://www.wolframalpha.com/input/?i=%5Cint_0%5E1+%5Cint_%7Bx%5E2%7D%5E%7Bsqrt%28x%29%7D+%28x%5E5%2By%5E5%29+dy+dx

anonymous · Answer

weird thats not an aswer choice

anonymous · Answer

the choices are 
a.1/37
b.1/18
c.1/32
d.3/32
e.5/32

ganeshie8 · Answer

wat are the options ?

anonymous · Answer

the answer you gave me is 5/32

anonymous · Answer

thats not equal to any of the fractions given above is it?

anonymous · Answer

let me grab my calculator and check

anonymous · Answer

1/18 is the closest

ganeshie8 · Answer

not sure 3/52 has to be the answer

ganeshie8 · Answer

check the question once

anonymous · Answer

it says

anonymous · Answer

Find the volume under z=x^5+y^5 and above the region bounded by y=x^2 and x=y^2

anonymous · Answer

it matches what I wrote previously

anonymous · Answer

might have been a typo on the answer choices

ganeshie8 · Answer

okay 3/52 is the correct answer, and its not there in ur options.

anonymous · Answer

im just gonna make a note of it

anonymous · Answer

for the professor

anonymous · Answer

thanks again for your help and are you here tomorrow as well

anonymous · Answer

would like it if you can help me on the remaining problems I have

anonymous · Answer

and what did you study in college that you know so much hehe?

ganeshie8 · Answer

il be around, but id like u to watch the videos first

ganeshie8 · Answer

after calcII, i just watched below videos one by one : http://ocw.mit.edu/courses/mathematics/18-02-multivariable-calculus-fall-2007/video-lectures/

anonymous · Answer

Yes I am going to try to watch the videos for sure if I can get around to it tomorrow after work

anonymous · Answer

if not could you still help me this work is due monday for cal 2 hehe