Question

I have already done half of the work and simplified it

Answer 1

\[\frac{ 6x ^{2}- 5x - 3 }{ x ^{2}-2x +6 } \le 4\]

Answer 2

Then the least ans the highest values of 4x^2 are

Answer 3

and*

Answer 4

Let's see you try,

Answer 5

I have already done half of the work and simplified it wait

Answer 6

\[\frac{ 2x ^{2} + 3x - 27 }{ x ^{2} - 2x + 6 }\]

Answer 7

if you make factors, will it work...

Answer 8

all that is less than or equal to 0

Answer 9

We have to use quadratic formula simple factorisation won't work here

Answer 10

yup... then what will be the result...

Answer 11

the answer is 0 and 81 i don't know how they got it

Answer 12

Or probably i have made some mistake in calculating

Answer 13

no i haven't i checked it

Answer 14

it will be good, to post the exact question here....

Answer 15

that is the question

Answer 16

i posted it . It is exact

Answer 17

ok

Answer 18

\[6x^2 -5x-3 \le 4(x^2 -2x+6)\]
\[2x^2 +3x-27 \le 0\]
\[(2x+9)(x-3) \le 0\]
\[-\frac{9}{2} \le x \le 3\]

Answer 19

thats just the numerator right

Answer 20

so about the denominator

Answer 21

we can't factorise

Answer 22

no you get rid of fraction by multiplying the denominator over to right side

Answer 23

it

Answer 24

We don't know if the denominator is positive or not if it was positive infact we could have done it