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Calculus1
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integration
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\[\int\limits_{1}^{2}(x-1)\sqrt{2-x } dx\]
did you try substituting u= 2-x ?
no i didn't
one question at a time
ok sorry
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then try it now!
u = 2-x du = ... new upper limit = ... new lower limit = ...
du=-dx new upper limit=-1 new lower limit =1 right?
when x = 2 u = 2-x = 2-2 = 0 how u got -1 ?
oh, you took limits of 2nd integration ? :P
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oh sorry i took the limit of the second one lol
so whats your new integral look like ?
hmm alright, maybe we can start by distributing out the x-1 |dw:1399196251540:dw| so the second part we can do fairly easy with a u substitution are you familiar with that technique?
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