Question

Checking my answer: Find the equation of the line that is perpendicular to the tangent line to the curve, y=(3x+1)/(4x-2)

Answer 1

at point (1,2)

Answer 2

I used the quotient rule to get -10/(8x^2 -16x+4)

Answer 3

Plugged in 1 to get 5/2

Answer 4

Since it is perpendicular the slope is the negative reciprocal, so -2/5

Answer 5

my final answer is y-2=(-2/5)(x-1)

Answer 6

derivative i got is -5/2
not +5/2

Answer 7

ah yes that's right

Answer 8

isn't the first term of the denominator
\(\Large 16x^2\)

Answer 9

and not 8x^2

Answer 10

well I did (4x-2)(4x-2)

Answer 11

yeah, first term = 4x*4x = 16x^2

Answer 12

lol

Answer 13

of course

Answer 14

so slope = -5/2 :)

Answer 15

y-2=(2/5)(x-1)

Answer 16

Cool, I'll try to be more careful next time ^_^

Answer 17

thanks

Answer 18

welcome ^_^