Question

@hartnn

Answer 1

\[\int\limits_{1}^{3} x \left[ x \right] dx\]

Answer 2

[x] is the floor function ?

Answer 3

yes

Answer 4

you will need to break this function into intervals

1 to 3
= 1 to 2 + 2 to 3
have you broken an integral like this before ?

Answer 5

for the interval, 1 to 2
floor (x) = ... ?

Answer 6

for the interval, 2 to 3
floor (x) = ... ?

you know what floor function is, right ?

Answer 7

yes i know it
for the interval, 2 to 3 floor (x) = 2
for the interval, 1 to 2 floor (x) = 1

Answer 8

right ?

Answer 9

yes
plug these in