Put the following radical expression into simplified form.
\[\sqrt[3]{\frac{ 4 }{ 5 }}\]
\[\frac{ \sqrt[3]{4} }{ \sqrt[3]{5} }\] That's the only part I know lol
@hartnn
\(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{4} }{ \sqrt[3]{5} } }\) multiply top and bottom times ³√5 (cube root of 5) in order to get rid of the radical in the denominator.
\(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{4} }{ \sqrt[3]{5} } }\) multiply top and bottom times ³√5 (cube root of 5) in order to get rid of the radical in the denominator.
I mean cube root of 25, so that you would have (on the bottom, cube root of 125, which is equal to 5.
\(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{4} }{ \sqrt[3]{5} } }\) \(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{4}\color{red} { \times \sqrt[3]{25} } }{ \sqrt[3]{5}\color{red} { \times \sqrt[3]{25} } } }\) \(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{4\times 25} }{ \sqrt[3]{5\times 25} } }\) \(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{100} }{ \sqrt[3]{125} } }\) \(\LARGE\color{blue}{ \bf \frac{ \sqrt[3]{100} }{ 5 } }\) THERE :)
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