Question

Prove that....

Answer 1

\[\huge \log 540 = 2\log2 + 3\log3 + \log 5 \]

Answer 2

I got what you are saying

Answer 3

\(\Large a\log b = \log b^a\)

Answer 4

finally! :P

Answer 5

so
2 log 2 = ...
3 log 3 = ...

Answer 6

log ( 2 * 27 * 5)

Answer 7

shouldn't there be 4 instead of 2 ?

Answer 8

yes sorry typying mistake

Answer 9

log ( 4 * 27 * 5)

Answer 10

then 4*27*5 is indeed 540

Answer 11

yes absolutely after that!

Answer 12

any doubts ?

Answer 13

the question is not completed

Answer 14

i mean the answer isn't i think so we have to prove

Answer 15

2log2+3log3+log5

Answer 16

we proved it...we took the right side, and proved it to left side...

Answer 17

SO,
log 2^2 + log 3^3 + log5
2log2 + 3log3 + log5

Answer 18

yes thank you !!

Answer 19

welcome ^_^