Diff Eq dy/dx=(y^2-y)/cosx, y(o)=1/2

Question

mathmale · Answer

You might find this problem easier to understand, as I do, if you'd write it in Equation Editor:$$\frac{ dy }{ dx }=\frac{ y^2-y }{ \cos x }$$

mathmale · Answer

This appears to be a SEPARABLE differential equation.  Please separte it, so that all the x-terms are on one side of your equation, and all y-terms are on the other.  Then ask yourself:  what next?

mathmale · Answer

@AlexLyu ??  Please become involved in solving this d. e.   If you're not sure of what to do next, please ask questions.

anonymous · Answer

Hi, thanks for the reply, after doing the separable, i got stuck on how to solve the integral 1/cosx.

mathmale · Answer

Just re-write 1/cos x as sec x.
There is an integration formula for sec x.

accessdenied · Answer

Were you still having trouble with this problem because you bumped it?  If so, please tell us your issue!  :)