Line s passes through the points (2, 7) and (6, 1). Line t passes through the point (5, 2) and is perpendicular to line s. What is the equation for line t?
To write the equation of a line, you need the slope, and either the y-intercept or a point. Since you have a point, we can write it in point slope form, which is (y-y1)=m(x-x1). But you'd still need to find the slope for line t. If the two lines are perpendicular, then the slope of line t is the negative reciprocal of the slope of line s. So the best way to do this (i think) would be Find the slope of line s using the two points given Find the reciprocal, and multiply times -1. This is the slope of line t, or m Then plug this into your point slope equation. You'll get y-2=m(x-5). You'll need to plug in m, of course. Once you finish that, you'll have an equation. If your equation needs to be in slope intercept form, which is y=mx+b, then take your equation and solve for y. Hope this helps!
Thank you very much for you assistance. Your clarification has assured me on the solution.
No problem, glad to help!
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