What is the slope of the line that goes though (6, 5) and (3, 1)? 1. 3/4 2. -3/4 3. 4/3 4. -4/3
You will want to use the slope formula which is y2-y1/x2-x1
to get slope you do y2-y1/ x2-x1 .. you would do (5-1)/(6-3) which is 4/3
So when plugged in your equation will read: 1-5/3-6
Ok
The slope of a line calculated from tbhe coordinates of two points on the line is: \(\bf slope = \dfrac{\bf difference~~ in~~ y}{\bf difference~~in~~x} \)
Calculate the difference in the y-values. Calculate the difference in the x-values. Divide the first difference by the second difference.
You must make sure you calculate both differences the same way. That means, if the points are (a, b) and (c, d) and you decide to do the difference in y as d - b, then the difference in x must be in the same order, and it has to be c - a. If you want to do the difference in y as b - d, then the difference in x must be a - b.
Let's do an example.
I think B is the answer.
Slope of line through points: (4, 3) and (2, 6) diff in y = 6 - 3 = 3 diff in x = 2 - 4 = -2 slope = (diff in y)/(diff in x) = 3/(-2) = -3/2
Now your problem. What is the difference in y? 5 - 1 = 4 What is the difference in x? 6 - 3 = 3 slope = (diff in y)/(diff in x) = 4/3 Which choice is that?
B
I mean C
Isn't B -3/4?
Oh, ok, that's better.
Answer is C.
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