olve for x: −5|x + 1| = 10
x = 0
x = −3 and x = 1
x = −1 and x = 3
No solution
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OpenStudy (paki):
simple..... just do this....
−5(x + 1) = 10 and −5(x + 1) = -10... now solve....
hartnn (hartnn):
when you divide by -5 on both sides ,what do u get ?
hartnn (hartnn):
remember :
|....| can never be negative!
OpenStudy (anonymous):
-5x-5=10
=-3
OpenStudy (anonymous):
so 3
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hartnn (hartnn):
no...
first step is to divide both sides by -5
in −5|x + 1| = 10
what do u get ?
OpenStudy (acxbox22):
no just divide by -5 on both sides
those arent parentheses it is the absolute value symbol
paki got u confused...
OpenStudy (anonymous):
i have no clue
OpenStudy (acxbox22):
what is 10/-5???
OpenStudy (anonymous):
-2
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hartnn (hartnn):
yes,
so u get
|x+1| = -2
right ?
OpenStudy (anonymous):
ya
hartnn (hartnn):
is that even possible ?
OpenStudy (anonymous):
no
hartnn (hartnn):
remember : answer to absolute value sign can never be negative
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hartnn (hartnn):
so whats your conclusion ?
OpenStudy (anonymous):
so its 2
hartnn (hartnn):
no, its not 2
since |x+1| can never = -2
there is no value of 'x' !
OpenStudy (anonymous):
so its no solution
hartnn (hartnn):
yessss :)
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
can you help me with one more please
hartnn (hartnn):
welcome ^_^
and since you're new here,
\(\Huge \mathcal{\text{Welcome To OpenStudy}\ddot\smile} \)
sure!
OpenStudy (anonymous):
thank you :)))
OpenStudy (anonymous):
-3|x + 7| = -12
x = 5 over 3, x = −19 over 3
x = −3, x = −11
x = −3, x = 11
No solution
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hartnn (hartnn):
divide both sides by -3
hartnn (hartnn):
always first try to isolate the absolute value sign
OpenStudy (anonymous):
4
OpenStudy (anonymous):
im really connfused with absolute values
OpenStudy (acxbox22):
now 4 is positive so go on to the next step,
x+7=4 and x+4=-7
now solve for x
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OpenStudy (anonymous):
-3 and -3
hartnn (hartnn):
general rule!
when |a| = b
we have a= b or a = -b
OpenStudy (acxbox22):
no..
x+7=4
subtract 7 on both sides
x+7=-4
subtract 7 on both sides
OpenStudy (anonymous):
nvm its -3 and -11
OpenStudy (acxbox22):
good job
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OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
and i have one more
OpenStudy (anonymous):
Solve for x: |2x + 6| − 4 = 20
x = 9 and x = 11
x = −9 and x = 15
x = 9 and x = −15
No solution
hartnn (hartnn):
add 4 on both sides...
OpenStudy (anonymous):
24
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OpenStudy (anonymous):
wait no
OpenStudy (anonymous):
9
hartnn (hartnn):
|2x+6| = 24
now use the general rule which i gave you!
hartnn (hartnn):
when |a| = b
we have a= b or a = -b
when
|2x+6|= 24
....?....
OpenStudy (anonymous):
9
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OpenStudy (anonymous):
is it no solution
OpenStudy (anonymous):
it has to be one of these
x = 9 and x = −15
x = 9 and x = 11
No solution
hartnn (hartnn):
9 is one of the solution, whats another ?
hartnn (hartnn):
2x+6 = 24 gave you x = 9
2x+6 = -24
gives you what ?
OpenStudy (anonymous):
-15
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OpenStudy (anonymous):
so its 9 and -15
hartnn (hartnn):
yes! correct :)
OpenStudy (anonymous):
Solve for x: |x + 2| + 16 = 14
x = −32 and x = −4
x = −4 and x = 0
x = 0 and x = 28
No solution
OpenStudy (anonymous):
is the answer to this one -32 and -4?
hartnn (hartnn):
this is easy
subtract 16 from both sides
what do u get ?
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hartnn (hartnn):
and no, thats not the answer
OpenStudy (anonymous):
-2
OpenStudy (anonymous):
i think its no solution
hartnn (hartnn):
can |x+2| ever be -2 ??
OpenStudy (anonymous):
no
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hartnn (hartnn):
correct, so its no solution :)
OpenStudy (anonymous):
The minimum and maximum temperature for a day in Cupcake Town can be modeled by the equation below:
3|x − 8| + 15 = 18
What are the minimum and maximum temperatures for this day?
x = 1, x = 17
x = −7, x = 9
x = 7 x = 9
No solution
OpenStudy (anonymous):
is this one x=7 x=9
hartnn (hartnn):
ask new question in a new post :)
so that others can help you too!
bdw, you are correct for this :)
OpenStudy (anonymous):
ok thanks
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