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OpenStudy (anonymous):
\[a ^{x} = e ^{(x)\ln a }\]
OpenStudy (anonymous):
@AccessDenied
OpenStudy (anonymous):
@iPwnBunnies
OpenStudy (anonymous):
@hartnn
OpenStudy (anonymous):
@ganeshie8
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OpenStudy (accessdenied):
Did you have any ideas on how to approach this so far?
OpenStudy (anonymous):
I only know the basic properties of natural logs.
for example: e^(lna) = a
OpenStudy (accessdenied):
Yup. How about the property for a power to a power?
\( (x^a)^b = x^{ab} \)
OpenStudy (anonymous):
Yes. I am also familiar with that property. My question here is how to apply these properties to the formula provided.
OpenStudy (accessdenied):
I think we should try to convert the right-hand side into the left.
\( a^x = e^{x \ln a} \)
We have x times ln a. So how about we apply the power to a power property and rewrite it so that:
\( e^{x \ln a} = e^{(\ln a ) x} = \left( e^{\ln a} \right)^x \)
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OpenStudy (anonymous):
@AccessDenied Ohhhh! I knew that but this question dazzled me for while. Thanks a lot mate, I really appreciate your effort.