Can someone help me prove this:
\[a ^{x} = e ^{(x)\ln a }\]
@AccessDenied
@iPwnBunnies
@hartnn
@ganeshie8
Did you have any ideas on how to approach this so far?
I only know the basic properties of natural logs. for example: e^(lna) = a
Yup. How about the property for a power to a power? \( (x^a)^b = x^{ab} \)
Yes. I am also familiar with that property. My question here is how to apply these properties to the formula provided.
I think we should try to convert the right-hand side into the left. \( a^x = e^{x \ln a} \) We have x times ln a. So how about we apply the power to a power property and rewrite it so that: \( e^{x \ln a} = e^{(\ln a ) x} = \left( e^{\ln a} \right)^x \)
@AccessDenied Ohhhh! I knew that but this question dazzled me for while. Thanks a lot mate, I really appreciate your effort.
Glad to help! :)
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