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Mathematics 6 Online
OpenStudy (anonymous):

Which part of the graph best represents the solution set to the system of inequalities y ≤ x + 1 and y + x ≤ –1?

OpenStudy (anonymous):

OpenStudy (anonymous):

any ideas

OpenStudy (anonymous):

@PinkSapphire any ideas :O

OpenStudy (anonymous):

@mathmale @MathLegend

OpenStudy (anonymous):

@halorazer

OpenStudy (pinksapphire):

First, get y by itself for the second equation so after you do it, it will look like this: \[y \le-1-x\]

OpenStudy (anonymous):

ok so y int 0.-1 and rise over run -1 /1 ?

OpenStudy (pinksapphire):

Your slope is -x and your y-intercept is -1

OpenStudy (anonymous):

ight

OpenStudy (pinksapphire):

So find each equation in the graph. Which one goes with which?

OpenStudy (anonymous):

i dont really get it ?

OpenStudy (anonymous):

like its the line touvching grahp d?

OpenStudy (anonymous):

confused af

OpenStudy (pinksapphire):

There are two lines on the graph right? Pretend that the colors are not there right now...

OpenStudy (anonymous):

ok 2 lines ignore colours then what xD

OpenStudy (pinksapphire):

Let's start with the first equation...\[y \le x+1\] What's the y-intercept and the slope of the line?

OpenStudy (pinksapphire):

I mean the equation...

OpenStudy (anonymous):

slope 1, y int 1?

OpenStudy (pinksapphire):

Yes, so now which line does the equation work with?

OpenStudy (pinksapphire):

The one that increases or decreases?

OpenStudy (anonymous):

the 1 going from bottom Left to top riight?

OpenStudy (pinksapphire):

Yes, correct! That line is increasing-remember that okay?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so whats the next step to find which section

OpenStudy (pinksapphire):

Plug in 0 for x and y. \[0 \le 0+1\] \[0 \le 1\] Is 0 less than or equal to 1? Is this inequality true? If it is than color the part where (0,0) is.

OpenStudy (anonymous):

yuh it is but i dont get what u said after that o_O

OpenStudy (pinksapphire):

It's hard to explain...wait a second.

OpenStudy (pinksapphire):

What is this topic called again? I forgot :(

OpenStudy (anonymous):

systems of linear equations i thinkkk

OpenStudy (pinksapphire):

Watch this video: http://www.youtube.com/watch?v=r5imr_kvk6M

OpenStudy (anonymous):

ok thanks im hopeless at maths ;)

OpenStudy (pinksapphire):

Do you get it?

OpenStudy (anonymous):

im gona watvh the vid i get tight up 2 the adding the 0 bit, is it D ?

OpenStudy (pinksapphire):

Correct! Good job!

OpenStudy (anonymous):

i actually love you hahah , will u help me with 1 more:o

OpenStudy (pinksapphire):

Okay :)

OpenStudy (anonymous):

The tables below show the values of f(x) and g(x) for different values of x. f(x) = 2(3)x x f(x) -2 0.22 -1 0.67 0 2 1 6 2 18 g(x) = 3x + 9 x g(x) -2 9.11 -1 9.33 0 10 1 12 2 18 Based on the tables, what is the solution to the equation 2(3)x = 3x + 9? x = 0 x = 2 x = 12 x = 18

OpenStudy (pinksapphire):

You should ask someone else to help you on this one...I haven't learned it yet. Sorry :(

OpenStudy (anonymous):

ok np :)

OpenStudy (anonymous):

ty off b4 :)

OpenStudy (pinksapphire):

Okay bye :)

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