Question

What volume of carbon dioxide gas at 650 torr and 20°C would be formed from 2 g of sodium bicarbonate?

HCl + NaHCO3 → NaCl + CO2 + H2O

Answer 1

okay, so first things first, the equation should be balanced. Is it?

Answer 2

give me 2 secs i need to pee sorry I'm so public

Answer 3

lol kk

Answer 4

I'm back srry

Answer 5

no probs. So is the equation balanced?

Answer 6

i think so? it looks balanced

Answer 7

it is. i was just checking that you knew that it was as well.

so we have to work with the 2g of sodium bicarbonate, since it's all were given (we don't need to find the limiting reactant).

So convert the mass to moles, using the molar mass.

(divide the mass by the molar mass)

Answer 8

so its 2g/60g/mol?

Answer 9

the molar mass of NaHCO3 is 84 g/mol

Answer 10

so 2g/84g/mol?

Answer 11

yep.

So, like before, we need to set up a ratio with the moles and the coefficients.

\(\dfrac{moles~of~HCO_3}{1}=\dfrac{moles~of~CO_2}{1}\)

since the coefficients are both the same, then the moles produced are the same.

Answer 12

so 0.023g/mol/1=moles of co^2/1?

Answer 13

the units are 0.0238 moles, not g/mol

but yeah, that's the correct set up.

Answer 14

ok so it would just be 0.0238 moles

Answer 15

so now that you know the moles of \(CO_2\), and since this isn't at STP, use the ideal gas law: PV=nRT

Answer 16

yeah thats correct.

Answer 17

so p would be 0.0238 moles?

Answer 18

i meant v

Answer 19

nope.

P= pressure
V=volume (what you're looking for)
n=moles
R=constant
T=temp (in Kelvin)

Answer 20

and p is 650 torr

Answer 21

yep, so first identify all your values then just plug them in and solve.

Answer 22

wats the v?

Answer 23

V is what you're looking for in the question.

Have you determined which is which of the rest of the variables?

Answer 24

wats r?

Answer 25

R in this case is 62.364 L torr/ mol·K

Answer 26

ok

Answer 27

so plug in all your values and solve for V

Answer 28

remember that T must be in Kelvin (not celsius)

Answer 29

do u cancel units before multiplying or after ?

Answer 30

whenever you want

Answer 31

so its 11883.29?

Answer 32

hm thats the volume you got?

Answer 33

if so, thats not correct.

did you divide by the pressure?

Answer 34

yes

Answer 35

let me do it again?

Answer 36

28.126?

Answer 37

\(V=\dfrac{62.364~L ·torr/ mol·K*0.0238~moles*(20+273.15)K}{650 torr}\)

is this what you did?

Answer 38

i got V=0.669402 L = 0.7 L

Answer 39

i didn't add the 4 on 62.364

Answer 40

that shouldn't be a big problem though. You should try getting the same answer as me with your calculator

Answer 41

idk mac calculators are weird

Answer 42

hm i use this website http://web2.0calc.com

Answer 43

no i got the same as u my computer was actin weird

Answer 44

oh ok, good stuff !

Answer 45

so thats the final answer, the volume of CO2

Answer 46

do u want me to post the other questions?

Answer 47

sure, post one at a time though.

Answer 48

ok