Question

Choose the equation below that represents the line passing through the point (-3, -1) with a slope of 4.

y - 1 = 4(x - 3)
y + 1 = 4(x + 3)
y - 3 = 4(x + 1)
y + 3 = 4(x - 1)

Answer 1

the one that looks like
\[\large y-\color{red}{y_1}=\color{blue}m(x-\color{green}{x_1})\] with
\[\large \color{red}{y_1}=\color{red}{-1},\color{blue}m=\color{blue}4,\color{green}{x_1}=\color{green}{-3}\]

Answer 2

thank you @satellite73 do you mind helping me with 2 more?

Answer 3

not at all
did you get the right answer for this one?

Answer 4

yes @satellite73 here are the 2 last ones i need help with, they're kinda confusing.

1. Choose the equation below that represents the line passing through the point (-2, -3) with a slope of -6.

y = -6x - 15
y = -6x - 20
y = -6x + 15
y = -6x + 20

2. Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7.

y = x + 8
y = x - 4
y = x + 4
y = x - 8

Answer 5

ok we start just as before, with \[y-(-3)=-6(x-(-2))\] or just
\[y+3=-6(x+2)\] but this now you have to solve for \(x\)
the steps are always the same
distritute first on the right and get
\[y+3=-6x-12\] then subtract \(3\) to get
\[y=-6x-15\]

Answer 6

can you do the second one?

Answer 7

ok let me try one second @satellite73

Answer 8

ok i got the first one but im having a bit trouble with the second one @satellite73