Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

How do i Do this?http://prntscr.com/3gb8ma

OpenStudy (anonymous):

Not clear what the question is , but for general triangles, Law of Sines is a/sinA = b/sinB =c/sinC and Law of Cosines c^2 = a^2 + b^2 - 2 a b cos C one or both should help

OpenStudy (anonymous):

which should i use

OpenStudy (anonymous):

I am distracted now. Play around with this a bit.

OpenStudy (anonymous):

ummm ok...

OpenStudy (anonymous):

can you use this as an example i hve 7 more problems and i hve no idea how to do it?

OpenStudy (anonymous):

Looks like Law of Sines will work. Do thse one triangle at a time to get the unknown side length.

OpenStudy (anonymous):

im doing the left triangle first so sin30/6 = Sin C/10 is this correct?

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

6/sin 30 = 10 / sin w the get s from the fact that s + w + 30 = 180

OpenStudy (anonymous):

6/sin 30= 12

OpenStudy (anonymous):

and then 10 divided by what

OpenStudy (anonymous):

get z from w+z = 180 for straight line get v from law of sines and 6/sin v get t from t=z+v = 180 get x from law of sines for x / sin t

OpenStudy (anonymous):

get t from t+z+v = 180 I don't see a "12" in the picture

OpenStudy (anonymous):

i put it in my calculator

OpenStudy (anonymous):

how do i get w. 180-30 is 120?

OpenStudy (anonymous):

6/sin30 = 10 / sin w so sin w = 10 sin 30 / 6 = 10(0.5)/6 = .833 w = arc sin (.833) = 56.4 o

OpenStudy (anonymous):

z= 93.6

OpenStudy (anonymous):

z = 180 - 56.4 = 123.6 a straight line through a point is a 180 degree angle.

OpenStudy (anonymous):

wow ok, so to get t i have to find v and to get v

OpenStudy (anonymous):

that's the idea, step by step, going from one to the next.

OpenStudy (anonymous):

yes but im missing someething to get v i have to know T, how do I get T?

OpenStudy (anonymous):

oh s=20 and t=100 because A=30, and 30+20+100=180?

OpenStudy (anonymous):

i mean wait

OpenStudy (anonymous):

s= 50?

OpenStudy (anonymous):

w = 56.4 from law of sines above 30 + w + s = 180 because angles in triangle sum to 180 o 30 + 56.4 + s = 180 s=?

OpenStudy (anonymous):

How are you doing?

OpenStudy (anonymous):

im trying to find V

OpenStudy (anonymous):

v= 34

OpenStudy (anonymous):

or 60

OpenStudy (anonymous):

@douglaswinslowcooper

OpenStudy (anonymous):

6/sin z = 6/ sin v you have z so sin z = sin(93.6) = 0.998 and v = z =93.6 Perhaps I've made a mistake, or the drawing is misleading, but z looks smaller than 90o though I have calculated it to be larger. We know I'm wrong because z+ v > 180. Sorry. 6/sin 30 = 10/sin w sin w = (10/6) sin (30) = 0.833 arc sin(0.833) = 56.4 which is too small an angle. Right now, I am puzzled.

OpenStudy (anonymous):

10/sin w = 6 / sin 30 sin w = (10/6) sin 30 = 0.833 w = 56.4 over and over again, But this makes 180 = w + z = 56.4 + z and z = 180 -56.4 etc. and z=v means z cannot be this big. I am sorry to have led yu astray. You might try strting from the right-side triangle, where z = v

OpenStudy (anonymous):

The problem seems straightforward, but I am making some mistake I cannot identify. Good night.

OpenStudy (anonymous):

Here's a link for Law of Sines. I cannot see my error. http://www.mathwarehouse.com/trigonometry/law-of-sines/formula-and-practice-problems.php

OpenStudy (anonymous):

Trying again. Perhaps the problem is that w>90 o. Start with v. Same law of sines give v=56.4. z = v because they subtend equal sides so v = 56.4 w+z= 180 because they split a straight line so w = 123.6 Sine w = sine (123.6) = 0.833 = sine (56.4), so there is our problem, sine has same value for these two angles, which are the same angular distance from 90 o. Get s, get t from sum of angles in triangle = 180 o. get x and y from law of sines again. Good luck..

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!