Acertain radioactive material decays according to the law A= A(sub0)e^-0.0277t, where A(sub0) is the initial amount present and A is the amount present in t years. What is the half-life of this material? Round the answer to two decimal places. (Hint: the half-life is the time required for A to be reduced to A(sub0)/2)

Question

anonymous · Answer

your job is to solve 
$$e^{-.0277t}=.5$$ for $t$ takes two steps

anonymous · Answer

write in equivalent logarithmic form as 
$$-.0277t=\ln(.5)$$ then divide by $-.0277$