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Mathematics 16 Online
OpenStudy (ria23):

Is anyone good with hyperbolas? If so, I would really appreciate the help.

OpenStudy (ria23):

There's four more.

OpenStudy (anonymous):

you got the center?

OpenStudy (ria23):

The center is (-1,3) right?

OpenStudy (anonymous):

you need a couple facts first you need the center then you need to know whether the \(y^2\) term comes first, or whether the \(x^2\) term comes first the center you should see with your eyeballs you see it?

OpenStudy (anonymous):

no, you have the \(x\) and \(y\) backwards

OpenStudy (anonymous):

right 3, down 1, center is \((3,-1)\) not \((-1,3)\)

OpenStudy (ria23):

Oh. ;o oops. (3, -1)

OpenStudy (anonymous):

ok so using that fact we know at least one thing there will be a \((x-3)^2\) term and a \((y+1)^2\) term is that part clear?

OpenStudy (ria23):

Yes.

OpenStudy (anonymous):

ok next question is it going to be \[\frac{(x-3)^2}{a^2}-\frac{(y+1)^2}{b^2}=1\] or is it going to be \[\frac{(y+1)^2}{b^2}-\frac{(x-3)^2}{a^2}=1\] i.e. which comes first you know that from the graph as well do you know which?

OpenStudy (ria23):

Uh... Wouldn't it be the first one? Because x goes before y...

OpenStudy (anonymous):

no it is not always the \(x\) first, that is for a coordinate

OpenStudy (anonymous):

|dw:1399260766344:dw|

OpenStudy (anonymous):

|dw:1399260790957:dw|

OpenStudy (anonymous):

clear?

OpenStudy (ria23):

Oh so it's y... Y is first... Right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

now we don't really have to worry about the denominators, although we could figure them out but you only have one choice that fits the bill we need

OpenStudy (ria23):

Oh wait... I got 'em backwards again... It's C.... Correct?

OpenStudy (ria23):

D* oy... I'm confusing myself... It would be D, because the -3 is with the x, right?

OpenStudy (anonymous):

hold on let me look again

OpenStudy (anonymous):

yeah D

OpenStudy (ria23):

c: Thank yhu. Can yhu help me with the others? I'm not understanding this unit, and my notes are confusing... And not very helpful.

OpenStudy (anonymous):

sure are they going to be like that one?

OpenStudy (ria23):

Sort of yes.

OpenStudy (anonymous):

k

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