Question

integral t^2+1/t^3 dt
where b=e^2 and a=e
I tried using u-substitution but I couldn't figure it out , can someone help me start the problem ?

Answer 1

What did you use a u-sub?

Answer 2

*as a

Answer 3

I tried with both, but I think u should be t^2+1

Answer 4

It should actually be u=t^3.

Answer 5

so if I let u=t^3 then du/3t^2= dt ?

Answer 6

oh heck no

Answer 7

break it in to two pieces and you will be done quickly

Answer 8

Wait... hold on.

Answer 9

Right, sorry, not thinking straight right now.

Answer 10

Okay so t^2/t^3 +1/t^3 and let u=t^3 ?

Answer 11

You could just integrate without a u-sub.

Answer 12

really
break it apart

Answer 13

\[\frac{t^2+1}{t^3}=\frac{1}{t}+\frac{1}{t^3}\]

Answer 14

Okay so when I broke it apart and used the du/3t^2 I get 1/3t^3 + 1/3t^2(t^3)

Answer 15

stop with the u

Answer 16

\(\frac{1}{t^3}=t^{-3}\)