Question

PLEASE HELP! Simplify (click to view screenshot)

Answer 1

@ganeshie8

Answer 2

@nincompoop

Answer 3

\[\huge x ^{\frac{ m }{ n }} = \sqrt[n]{x ^{m}} = (\sqrt[n]{x})^{m}\]

Answer 4

Can you please show me step by step if it's not too much trouble :/ @iambatman

Answer 5

@iambatman will hook you up, he is really a good helper.

Answer 6

First thing first, lets write out the problem here ^.^

Answer 7

\[\frac{ 21\sqrt[3]{2500} }{ 28\sqrt[3]{4} }\]

Answer 8

Now we have to find the greatest common denominator. So any idea what the gcd, is of 21, and 28?

Answer 9

\[\huge \frac{ 21\sqrt[3]{2500} }{ 28\sqrt[3]{4} } = \frac{ 7 }{ 7 }\times\frac{ 3\sqrt[3]{2500} }{ 4\sqrt[3]{4} }\]

Answer 10

I just factored out the 7s there.

Answer 11

Good job Batman! But I don't think he's there anymore. :c I gave you the medal, anyway.

Answer 12

Now you can simplify the radicals

\[\huge \frac{ 3\sqrt[3]{2500} }{ 4\times2^{2/3} }\]

Answer 13

I'm here! Sorry! I'm keeping up with the steps, thanks

Answer 14

Oh! My bad.

Answer 15

Alright :), so lets continue

Answer 16

\[\huge \sqrt[3]{2500} = \sqrt[3]{2^{2}\times5^{4}} = 5\times2^{2/3}\sqrt[3]{5}\]

Answer 17

Yeah it's a nasty one...

Answer 18

\[\huge \frac{ 3\times5\times2^{2/3}\sqrt[3]{5} }{ 4\times2^{2/3} } => \frac{ 15\sqrt[3]{5} }{ 4 }\]

Answer 19

And we're done, good day, hopefully that helped! :)

Answer 20

Thank you so much!! :D

Answer 21

Np :), it's an ugly one, I could see why people were avoiding this question ;)

Answer 22

*claps*

Answer 23

Lol @iambatman