A highway makes an angle of 6 degrees w/ the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the nearest hundredth of a mile, how high does the highway rise in this 5 mile section? Show steps
I was thinking |dw:1399270828094:dw|
tan 6 degrees = x/5 Am I on the right track ?
you know here "theta" is 6 degrees... so using the relation... tan(6) = rise/5 rise = 5*tan(6) ... solve now....
yup your procedure is Also rite...
what you got the value of rise...
tan 6 = .105
5*tan 6 = .526
how you got .105 and .526...?
just do like this.... tan (6) = rise/5... rise = 5*tan(6)... so rise = 0.525 miles
@Shay17 now got it...
Ok .. i'm still confused
where....? i hope the calculations are all simple and easy...
They seem to be but I'm still confused on how I messed up
where you are confused... tell me...?
Idk how did I mess up I just wanna make sure I fully understand
ahhh. so then have a look on my calculation and hope you will be satisfied... :)
Yes so what would a good explanation be ?
So wait the highway rises .53 miles in the 5 mile section ?
yes... in 5 miles it has a slope of 0.53 miles...
I'm good thank you I just had to re read it again ! :)
ahhh pleasure :)
@iambatman
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