Question

Is what i am doing correct
Question : 2log(7) - log 14

Answer 1

What are you trying to do?

Answer 2

log(49) - log(14)
log(49/14)

Answer 3

That looks right

Answer 4

@╰☆╮Openstudier╰☆╮ : Yes, you're correct.

Answer 5

Since 2log7 = log 7^2

Answer 6

well if you simply the fraction

49/14 = 7/2

so its log(7/2) = log(7) - log(2)

Answer 7

the answer given is
log5(49)(sqrt 3)

Answer 8

It depends if you need to simplify

Answer 9

so what is the base of the logs...?

Answer 10

5

Answer 11

ok... so they are both the same base...?

Answer 12

So pull the base out front and get 5log

Answer 13

we pull out the power right

Answer 14

what is the whole question... in what you have posted the question doesn't match the answer...

Answer 15

Question : 2log(7) - log 14

Answer 16

What is the base?

Answer 17

Simplify I assume, and the base is 10?

Answer 18

simplify yes

Answer 19

Ok the first part is log 7^2

Answer 20

log(49) - log(14)
log(49/14)

Answer 21

well the base doesn't matter as both logs are the same base....

so the normal log laws apply

so looking at it and applying the index laws for logs

\[2\log(7) - \log(14) = \log(7^2) - \log(14) = \log(49) - \log (14)\]

now the division law for logs

\[\log(49) - \log(14) = \log(\frac{49}{14}) = \log(\frac{7}{2})\]

that the job done...

Answer 22

If you are subtracting logs, then you divide them

Answer 23

Like @campbell_st mentioned it's log(7/2)

Answer 24

or log(7)-log(2) both work..

Answer 25

I got that my point is the answer given is
log5(49)(sqrt 3 )

Answer 26

that**

Answer 27

well I can't see the connection between the question and answer....

Answer 28

I don't see how the book got that, unless you were given a different base other than 10?

Answer 29

WELL the answer is incoorrect then

Answer 30

incorrect*

Answer 31

Can you post a screenshot/pic of the entire question?

Answer 32

based on the question and information you have provided.... unless there is something that been ommited...

Answer 33

log(7/2) is given in the next exercise to the excersise which i am doing currently so the answer is clearly misprinted
log(7/2) is correct

Answer 34

THANK YOU ALL OF YOU

Answer 35

lol.... never trust the answer in the back of the book