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Simplify each term, if necessary, and then use the distributive property to combine terms, if possible.
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\[\sqrt{108}+2\sqrt{12}-\sqrt{3}\]
factorise the terms under square roots into products of prime numbers
what are the prime factors of 108?
\[\sqrt{108}=6\sqrt{3}\]
\[2\sqrt{12}=2(2\sqrt{3})=4\sqrt{3}?\]
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@UnkleRhaukus
I did it !
that is good, \[\sqrt{108}+2\sqrt{12}-\sqrt{3}\] \[=6\sqrt{3}+4\sqrt{3}-\sqrt{3}\] now you can the distributive property \[ax+bx+cx=(a+b+c)x\]
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