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Mathematics 9 Online
OpenStudy (anonymous):

Consider the curve x=t^(2) , y= t^(3) from 0 ≦ t ≦ 2 a) Sketch the curve. b) Find the length of the arc of the curve that lies between (1,1) and (4,8). Please help me solving this qs!

OpenStudy (anonymous):

You good on sketching the curve?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

Okay, for the next part, the arc length can be found using the integral formula, \[L=\int_CdS=\int_a^b\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2}~dt\]

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

\[L=\int_1^2\sqrt{4t^2+9t^4}~dt\] Might require a trig sub...

OpenStudy (anonymous):

Or rather not, a simple algebraic sub will do the trick, after some preliminary rewriting.

OpenStudy (anonymous):

Alright !

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

yw

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