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OpenStudy (anonymous):
SOLVE FOR X
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OpenStudy (anonymous):
\[\huge 2\log10(x) = 1+ \log10(x+\frac{ 11 }{ 10 })\]
ganeshie8 (ganeshie8):
\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\]
ganeshie8 (ganeshie8):
use below :
\(1 = \log_a a\)
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
wait
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ganeshie8 (ganeshie8):
kk
OpenStudy (anonymous):
wait
ganeshie8 (ganeshie8):
\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\]
\[2\log_{10}(x) = \log_{10} 10+ \log_{10}(x+\frac{ 11 }{ 10 })\]
ganeshie8 (ganeshie8):
see if u can simplify and get rid of logs..
OpenStudy (anonymous):
10x^2 -10x -111 =0
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ganeshie8 (ganeshie8):
\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\]
\[2\log_{10}(x) = \log_{10} 10+ \log_{10}(x+\frac{ 11 }{ 10 })\]
\[\log_{10}(x^2) = \log_{10}10(x+\frac{ 11 }{ 10 })\]
\[\log_{10}(x^2) = \log_{10}(10x+11 )\]
\[x^2 = 10x+11\]
OpenStudy (anonymous):
I typed extra 1 by mistake
ganeshie8 (ganeshie8):
okay :)
ganeshie8 (ganeshie8):
you can solve this for x
OpenStudy (anonymous):
yes
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ganeshie8 (ganeshie8):
and dont forget to discard NEGATIVE values as log cnnot suck in negative stuff
OpenStudy (anonymous):
yes 11 is the answer
ganeshie8 (ganeshie8):
good :)
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