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Mathematics 14 Online
OpenStudy (anonymous):

SOLVE FOR X

OpenStudy (anonymous):

\[\huge 2\log10(x) = 1+ \log10(x+\frac{ 11 }{ 10 })\]

ganeshie8 (ganeshie8):

\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\]

ganeshie8 (ganeshie8):

use below : \(1 = \log_a a\)

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

wait

ganeshie8 (ganeshie8):

kk

OpenStudy (anonymous):

wait

ganeshie8 (ganeshie8):

\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\] \[2\log_{10}(x) = \log_{10} 10+ \log_{10}(x+\frac{ 11 }{ 10 })\]

ganeshie8 (ganeshie8):

see if u can simplify and get rid of logs..

OpenStudy (anonymous):

10x^2 -10x -111 =0

ganeshie8 (ganeshie8):

\[2\log_{10}(x) = 1+ \log_{10}(x+\frac{ 11 }{ 10 })\] \[2\log_{10}(x) = \log_{10} 10+ \log_{10}(x+\frac{ 11 }{ 10 })\] \[\log_{10}(x^2) = \log_{10}10(x+\frac{ 11 }{ 10 })\] \[\log_{10}(x^2) = \log_{10}(10x+11 )\] \[x^2 = 10x+11\]

OpenStudy (anonymous):

I typed extra 1 by mistake

ganeshie8 (ganeshie8):

okay :)

ganeshie8 (ganeshie8):

you can solve this for x

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

and dont forget to discard NEGATIVE values as log cnnot suck in negative stuff

OpenStudy (anonymous):

yes 11 is the answer

ganeshie8 (ganeshie8):

good :)

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