Question

Evaluate the indefinite integral
(a+bx^35)/(sqrt of (36ax+bx^36))dx
u=36ax+bx^36 and (1/36)du=(a+bx^35)dx
please help

Answer 1

good so far!
now plug all those into your original integral!
and make a new integral

Answer 2

numerator = (a+bx^35) dx = du/36
denominator = sqrt of (36ax+bx^36) = sqrt u

Answer 3

(1/36)*(u^(1/2)/(1/2))+C

Answer 4

before integration, its sqrt u ,right ???

Answer 5

so, u^(1/2) before integration
what will you get after integration ?

Answer 6

cos ? 13/2 ?
where does those come from ? :O

Answer 7

wrong problem