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Chemistry 19 Online
OpenStudy (anonymous):

I don't think this is that complicated. I am just not sure. "For the reaction A = products time and concentration data were collected...

OpenStudy (anonymous):

OpenStudy (aaronq):

the instantaneous rate is the first derivative to the curve, which is really just the slope at that point. Notice they drew a tangent (in yellow) to the curve at that point, so just find the slope of that line. \(rate=\dfrac{0.16M-0.48M}{93s-0s}=-0.0034408~M/s\) note that it's negative because it's in terms of [A].

OpenStudy (aaronq):

They want the positive value because they're asking for the rate of the reaction not the consumption of A.

OpenStudy (anonymous):

Thanks! I was not sure what points to use. But you use the ends of the graph.

OpenStudy (aaronq):

no problem! yeah i went with that because it's the easiest, but you can take any points along the line, it'll give you the same value.

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