Question

Prove the identity? Medal and fan :)

Answer 1

\[\tan \theta = 1 - \cos 2 \theta/ \sin2\theta\]

Answer 2

use double angle identity
\[\cos 2 \theta = \cos^2 \theta - \sin^2 \theta\]
\[\sin 2 \theta = 2 \sin \theta \cos \theta\]

Answer 3

I know that much, Idk how to set it up @dumbcow

Answer 4

ok well did you substitute in, then make a simplification

--> 1- cos^2 = sin^2

Answer 5

Yeah I have, I spent so long on this. I don't know what I'm doing wrong @dumbcow

Answer 6

\[\frac{1 - (\cos^2 - \sin^2)}{2 \sin \cos} = \frac{2 \sin^2}{2 \sin \cos} = ?\]
did you get this far

Answer 7

Uh no?

Answer 8

lol you just said you substituted in for sin(2x) and cos(2x) and simplified using pythagorean thm

Answer 9

The only thing I did that I know is right so far is \[1- \cos ^2 \theta - \sin ^ 2 \theta / 2 \sin \theta \cos \theta\]

Answer 10

@dumbcow

Answer 11

no its
1 - (cos^2 - sin^2) = (1 - cos^2) + sin^2 = sin^2 + sin^2 = 2 sin^2