Question

A car moving at a speed of 20 m/s, then accelerates uniformly at 1.8m/s2 until it reaches a speed of 25m/s. What distance does it travel during the time it is accelerating?

Answer 1

@douglaswinslowcooper

Answer 2

@NERD85176

Answer 3

\[a=\frac{ V_{f}-V_{i} }{ t }\]
So we have a, Vi and Vf. So we need t:
\[t=\frac{ V_{f}-V_{i} }{ a }\]
\[t=\frac{ 25\frac{ m }{ s }-20\frac{m }{ s } }{ 1.8\frac{ m }{ s^{2} } }\]

Answer 4

t=\[\frac{ 25 }{ 9 }\]\[x_{f}-x_{i}=v_{0}t+\frac{ 1 }{ 2 }at ^{2}\]
\[d=20(\frac{ 25 }{ 9 })+\frac{ 1 }{ 2 }(1.8)(\frac{ 25 }{ 9 })^{2}\]

Answer 5

d=64.34461806 m

I got those formulas from the internet

Answer 6

Ohh I think I had a mistake it is
d=125/2=62.5. I