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Mathematics 15 Online
OpenStudy (anonymous):

Prove: cos θ - cos θ•sin2 θ = cos3 θ. You must show all work.

OpenStudy (anonymous):

@mathissuperhard23

OpenStudy (anonymous):

@calculusxy

OpenStudy (anonymous):

Hey, I might be able to help. I haven't done these in a while though so it might take some trial and error.

OpenStudy (anonymous):

Have you tried proving it already?

OpenStudy (anonymous):

yes i have but i can't seem to get it

OpenStudy (anonymous):

Ok, I will give it a try

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

Is cosx - (cosx)(sin2x) = cos3x correct? I just want to make sure nothing is missing

OpenStudy (anonymous):

I don't believe they are equal

OpenStudy (anonymous):

Okay I see what has happened. I thought it was cos(3x) but it is actually (cosx)^3

OpenStudy (anonymous):

Okay I can help you now. We should start with the left side because it is more complicated. Lets start by factoring out cosx

OpenStudy (anonymous):

You will then be left with cosx(1-sin^2(x)) and we know from our pythagorean identities that sin^2(x) + cos^2(x) =1 can be arranged to form 1-sin^2(x)=cos^2(x)

OpenStudy (anonymous):

So sub cos^2(x) for (1-sin^2(x)) and you will be left with cosx(cos^2(x)) which we can see will simplify to cos^3(x), proving the equation!

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