Prove: cos θ - cos θ•sin2 θ = cos3 θ. You must show all work.
@mathissuperhard23
@calculusxy
Hey, I might be able to help. I haven't done these in a while though so it might take some trial and error.
Have you tried proving it already?
yes i have but i can't seem to get it
Ok, I will give it a try
thank you so much
Is cosx - (cosx)(sin2x) = cos3x correct? I just want to make sure nothing is missing
I don't believe they are equal
Okay I see what has happened. I thought it was cos(3x) but it is actually (cosx)^3
Okay I can help you now. We should start with the left side because it is more complicated. Lets start by factoring out cosx
You will then be left with cosx(1-sin^2(x)) and we know from our pythagorean identities that sin^2(x) + cos^2(x) =1 can be arranged to form 1-sin^2(x)=cos^2(x)
So sub cos^2(x) for (1-sin^2(x)) and you will be left with cosx(cos^2(x)) which we can see will simplify to cos^3(x), proving the equation!
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