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Mathematics 23 Online
OpenStudy (anonymous):

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z} Determine the following. (B' ∩ C)' ∪ A A. {q, s, u, v, w, x, y} B. {q, s, u, y} C. {q, r, s, t, u, w, y, z} D. {q, r, s, t, u, v, w, x, y}

OpenStudy (reemii):

B' is the complementary set of B ?

OpenStudy (anonymous):

huh?

OpenStudy (reemii):

what is the meaning pf B' , or just ' in the line (B' ∩ C)' ∪ A ?

OpenStudy (anonymous):

not b

OpenStudy (reemii):

ok! you must construct this little by little. B = {q,s,y,z}. B' = ? then B'\(\cap\)C = ? then (B'\(\cap\)C)' = ? etc.

OpenStudy (anonymous):

b' all the rest of the letters

OpenStudy (reemii):

okay, can you write B'\(\cap\)C here ?

OpenStudy (anonymous):

bso would it be both b and c

OpenStudy (reemii):

It's what is in both B' and C, that's why you must list the elements of B' before. btw, is U the set of all letters?

OpenStudy (reemii):

answer A.

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