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Find \(z'(x)\)
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If \(z(x)=\int_{x}^{2} ln(t)~ dt\) then find \(z'(t)\)
\(z'(x)\)
Well, if you substitute \(t=x\) then \(z'(t)=z'(x)\).
\(\large z(x)(\frac{d}{dx})=(\frac{d}{dx})\int_{2}^{x} ln t~dt=z'(x)=-ln~x\)?
*\(= - (\frac{d}{dx})\int_{2}^{x} ln t~dt\)
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\((\int_x^2 ln(t)\ dt)' = \left(\int_0^2\ln(t)\ dt - \int_0^x \ln(t)\ dt\right)'\) Now apply the fundamental theorem to each term and \((\int_x^2 ln(t)\ dt)' = \left(\int_0^2\ln(t)\ dt - \int_0^x \ln(t)\ dt\right)' = \left(c - \int_0^x \ln(t)\ dt\right)' = 0 - \ln(x)\)
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