Factoring helpppp
10a^3b^4c-15a^3bc^2
I don't know what the greatest common factor there is in this problem
Lets start with the numbers 15 and 10... What is the biggest number we can pull out of both of them?
or perhaps I should say greatest common factor
5
right?
Yup, so lets divide both of those groups by 5
5(2a^3b^4c-3a^3bc^2) good so far?
ok thats fine and also i am confused on 3x^2+11x+6
so are you finished with the first question now? I didn't give you the full answer
I got 5a^3bc(2b^3-3c)
oo wait wrong problem
oo nvrmind it isn't the wrong one
yeah it looks good to me
ok thanks i think i am good
is this right? -11x^5y+22xy= -11xy(x^4+2)
remember that you can always check your work by reversing what you did (so multiplying -11xy by (x^4+2)
oo ok
but i am confused on when the gcf is a negative or positive
Well two negatives make a positive and two positives make a positive. If the signs are different, it will be negative. What part are you having trouble with?
but what about a problem like this... 8x^7y^4z+12xyz-16y^2z^3....... theres three different numbers
Find the gcf for all three groups, and then divide each group by the gcf. It is sometimes easier to understand if you put the gcf under each group of terms, because then you can concentrate on each one separately.
would it be 4 or -4?
honestly it doesn't really matter. usually you want the first term in the brackets to be positive. So -3(x+4) looks a lot better than 3(-x-4)
ok
Thanks for the medal. Let me know if you have anymore questions.
ok thanks
ok I tried to do....4x^2-5x-6 and got (4x+3) (x-2) but my teacher got (4x+3) (x-2x)... i don' t get why there is the x on right next to the 2
ok I will try
Your answer is correct. Remember that you can multiply out your answer to see if you get the stuff you were originally given. This is a great way to tell if you are right or not.
ya i think my teacher is wrong thanks i just didn't want to b confused
I need to get going now. Good luck with your homework.
thank you this really helped me for my test tomorrow :)
Join our real-time social learning platform and learn together with your friends!