Question

Question below

Answer 1

\[\Huge 4\left( 9^{x-1} \right) = 3\left( 2^{2x+1} \right)^{\frac{ 1 }{ 2 }}\]

Answer 2

Solve for x

Answer 3

@ganeshie8

Answer 4

i think u will need to use logs this time

Answer 5

This is in indices

Answer 6

doesnt matter, it wont simplify

http://www.wolframalpha.com/input/?i=solve++4%5Cleft%28+9%5E%7Bx-1%7D+%5Cright%29+%3D+3%5Cleft%28+2%5E%7B2x%2B1%7D+%5Cright%29%5E%7B%5Cfrac%7B+1+%7D%7B+2+%7D%7D

Answer 7

take log both sides

Answer 8

and isolate x

Answer 9

I got 1.5 is it correct

Answer 10

1.5 is correct ! how did u get it ? xD

Answer 11

I got it without taking logs actually i simplified it

Answer 12

interesting, could u show me plz

Answer 13

i dont see it yet how u can avoid logs :/

Answer 14

Yes i will type

Answer 15

\[4\left( 9^{x-1} \right) = 3\left( 2^{2x+1} \right)^{\frac{ 1 }{ 2 }}\]

\[4\left( 3^{2(x-1)} \right) = 3\left( 2^{x+\frac{1}{2}} \right)\]

\[\left( 3^{2(x-1)-1} \right) = \left( 2^{x+\frac{1}{2}-2} \right)\]

\[3^{2x-3} = 2^{x-\frac{3}{2}} \]

Answer 16

you will have to take log now

Answer 17

right ?

Answer 18

In the simplified version

Answer 19

not getting u

Answer 20

show me the complete solution if psble :)

Answer 21

I did it without logs long time back but since i ate up all the steps and wrote direct answers i am not getting how i did the marvel. But yes i am convinced now we have to take log here. But since this is in indices I am sure there must be a cunning method to tackle this. I will ask my prof. tommorow and get back to you as soon as possible.!
Thank you so much for your help.!

Answer 22

okay, this can wait :)

Answer 23

knw what, you're right ! this can be solved with out logs

Answer 24

HOw how!!!!!

Answer 25

\[3^{2x-3} = 2^{x-\frac{3}{2}}\]

Answer 26

the exponential curves \(y = 3^X \) and \(y = 2^X\) intersect only when \(X = 0\)

Answer 27

set the exponents equal to 0 and solve \(x \) :

\(2x-3 = 0 \implies x = \dfrac{3}{2}\)

\(x - \dfrac{3}{2} = 0 \implies x = \dfrac{3}{2}\)

Answer 28

it just has to strike u... xD

Answer 29

YEAH great a unique problem i must remember this kind of situation thanks !!!